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Definite Integrals of Even and Odd Functions | NIMCET

Learn how even and odd functions simplify definite integrals over symmetric limits, how to integrate periodic functions, and the Leibniz rule for differentiating integrals, with a NIMCET syllabus note.

4 min read

SP

SHIVAM PRADHAN

Updated 25 October 2026

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Quick answer: For an even function (f(−x)=f(x)f(-x) = f(x)), ∫−aaf(x) dx=2∫0af(x) dx\int_{-a}^{a}f(x)\,dx = 2\int_0^a f(x)\,dx. For an odd function (f(−x)=−f(x)f(-x) = -f(x)), ∫−aaf(x) dx=0\int_{-a}^{a}f(x)\,dx = 0. For a periodic function with period T, ∫0nTf(x) dx=n∫0Tf(x) dx\int_0^{nT}f(x)\,dx = n\int_0^T f(x)\,dx. The Leibniz rule gives ddx∫g(x)h(x)f(t) dt=f(h(x)) h′(x)−f(g(x)) g′(x)\frac{d}{dx}\int_{g(x)}^{h(x)}f(t)\,dt = f(h(x))\,h'(x) - f(g(x))\,g'(x).

Syllabus note: Reports on the revised NIMCET syllabus list definite integrals of even and odd functions, while the Leibniz rule and periodic functions are reported as removed. Check the official information brochure for your exam year; see our revised syllabus update.

This continues from definite integrals and King's property.

Even and odd functions

TypeConditionExamples
Evenf(−x)=f(x)f(-x) = f(x)x2x^2, cos⁡x\cos x, ∣x∣\lvert x\rvert, xsin⁡xx\sin x
Oddf(−x)=−f(x)f(-x) = -f(x)x3x^3, sin⁡x\sin x, tan⁡x\tan x, xcos⁡xx\cos x
NeitherNeither conditionexe^x, x+x2x + x^2
ProductResult
Even × evenEven
Odd × oddEven
Even × oddOdd

Any function splits as f(x)=f(x)+f(−x)2+f(x)−f(−x)2f(x) = \frac{f(x) + f(-x)}{2} + \frac{f(x) - f(-x)}{2} (even part + odd part). Only the even part survives in ∫−aa\int_{-a}^{a}.

Symmetric-limit results

Integrand∫−aaf(x) dx\int_{-a}^{a}f(x)\,dx
Even2∫0af(x) dx2\int_0^a f(x)\,dx
Odd0
General∫0a[f(x)+f(−x)] dx\int_0^a[f(x) + f(-x)]\,dx

Periodic functions

If f(x+T)=f(x)f(x + T) = f(x):

ResultStatement
Whole periods∫0nTf(x) dx=n∫0Tf(x) dx\int_0^{nT}f(x)\,dx = n\int_0^T f(x)\,dx
Shifted interval∫aa+Tf(x) dx=∫0Tf(x) dx\int_a^{a + T}f(x)\,dx = \int_0^T f(x)\,dx

Common periods: sin⁡x\sin x and cos⁡x\cos x have period 2π2\pi; ∣sin⁡x∣\lvert\sin x\rvert, tan⁡x\tan x and sin⁡2x\sin^2 x have period π; {x}=x−[x]\{x\} = x - [x] has period 1.

Leibniz rule

ddx∫g(x)h(x)f(t) dt=f(h(x)) h′(x)−f(g(x)) g′(x)\frac{d}{dx}\int_{g(x)}^{h(x)}f(t)\,dt = f(h(x))\,h'(x) - f(g(x))\,g'(x)

Worked examples

Example 1: an odd integrand

∫−11x3cos⁡x dx=0\int_{-1}^{1}x^3\cos x\,dx = 0

since x3cos⁡xx^3\cos x is odd.

Example 2: an even integrand

∫−22(x2+∣x∣) dx=2∫02(x2+x) dx=2(83+2)=283\int_{-2}^{2}(x^2 + \lvert x\rvert)\,dx = 2\int_0^2(x^2 + x)\,dx = 2\left(\frac{8}{3} + 2\right) = \frac{28}{3}

Example 3: mixed

Evaluate ∫−11(x5+3x2+sin⁡x) dx\int_{-1}^{1}(x^5 + 3x^2 + \sin x)\,dx.

The odd parts x5x^5 and sin⁡x\sin x vanish, leaving 2∫013x2 dx=22\int_0^1 3x^2\,dx = 2.

Example 4: a periodic function

Evaluate ∫010π∣sin⁡x∣ dx\int_0^{10\pi}\lvert\sin x\rvert\,dx.

The period is π and ∫0πsin⁡x dx=2\int_0^{\pi}\sin x\,dx = 2, so the answer is 10×2=2010 \times 2 = 20.

Example 5: fractional part

Evaluate ∫05{x} dx\int_0^5\{x\}\,dx.

∫01x dx=12\int_0^1 x\,dx = \frac{1}{2}, so the answer is 5×12=525 \times \frac{1}{2} = \frac{5}{2}.

Example 6: Leibniz rule

Find ddx∫xx2dtt\frac{d}{dx}\int_x^{x^2}\frac{dt}{t} for x>0x > 0.

1x2⋅2x−1x⋅1=2x−1x=1x\frac{1}{x^2} \cdot 2x - \frac{1}{x} \cdot 1 = \frac{2}{x} - \frac{1}{x} = \frac{1}{x}

Summary table

IdeaKey result
Odd over [−a, a]0
Even over [−a, a]Twice the integral over [0, a]
Periodic, n periodsn times one period
∣sin⁡x∣\lvert\sin x\rvertPeriod π, area 2 per period
Leibnizf(h)h′−f(g)g′f(h)h' - f(g)g'

Exam tips

  • With symmetric limits, check parity before doing any integration.
  • Split mixed integrands into odd and even parts.
  • For long intervals of periodic functions, find one period's value and multiply.

See the area under curves for geometric applications, and the NIMCET Calculus chapter.

Common mistakes

  • Using the odd-function result when limits are not symmetric.
  • Treating ∣x∣\lvert x\rvert or xsin⁡xx\sin x as odd.
  • Taking 2π2\pi as the period of ∣sin⁡x∣\lvert\sin x\rvert.
  • Forgetting the lower-limit term in the Leibniz rule.

Frequently Asked Questions

What is the integral of an odd function from −a to a?

It is 0.

What is the integral of an even function from −a to a?

It is 2∫₀ᵃ f(x) dx.

How do you integrate a periodic function over many periods?

Multiply the integral over one period by the number of periods.

What is the Leibniz rule?

d/dx ∫ from g(x) to h(x) of f(t) dt = f(h(x))h′(x) − f(g(x))g′(x).

Is the Leibniz rule in the NIMCET syllabus?

Reports on the revised syllabus list it as removed. Confirm with the official information brochure for your exam year.

Concept Check

MEDIUM

Which continuous probability distribution possesses the 'Memoryless Property': P(X>s+t∣X>s)=P(X>t)P(X > s + t \mid X > s) = P(X > t)?

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