Quick answer: For an even function (f(−x)=f(x)), ∫−aaf(x)dx=2∫0af(x)dx. For an odd function (f(−x)=−f(x)), ∫−aaf(x)dx=0. For a periodic function with period T, ∫0nTf(x)dx=n∫0Tf(x)dx. The Leibniz rule gives dxd∫g(x)h(x)f(t)dt=f(h(x))h′(x)−f(g(x))g′(x).
Syllabus note: Reports on the revised NIMCET syllabus list definite integrals of even and odd functions, while the Leibniz rule and periodic functions are reported as removed. Check the official information brochure for your exam year; see our revised syllabus update.
This continues from definite integrals and King's property.
Even and odd functions
| Type | Condition | Examples |
|---|
| Even | f(−x)=f(x) | x2, cosx, ∣x∣, xsinx |
| Odd | f(−x)=−f(x) | x3, sinx, tanx, xcosx |
| Neither | Neither condition | ex, x+x2 |
| Product | Result |
|---|
| Even × even | Even |
| Odd × odd | Even |
| Even × odd | Odd |
Any function splits as f(x)=2f(x)+f(−x)+2f(x)−f(−x) (even part + odd part). Only the even part survives in ∫−aa.
Symmetric-limit results
| Integrand | ∫−aaf(x)dx |
|---|
| Even | 2∫0af(x)dx |
| Odd | 0 |
| General | ∫0a[f(x)+f(−x)]dx |
Periodic functions
If f(x+T)=f(x):
| Result | Statement |
|---|
| Whole periods | ∫0nTf(x)dx=n∫0Tf(x)dx |
| Shifted interval | ∫aa+Tf(x)dx=∫0Tf(x)dx |
Common periods: sinx and cosx have period 2π; ∣sinx∣, tanx and sin2x have period π; {x}=x−[x] has period 1.
Leibniz rule
dxd∫g(x)h(x)f(t)dt=f(h(x))h′(x)−f(g(x))g′(x)
Worked examples
Example 1: an odd integrand
∫−11x3cosxdx=0
since x3cosx is odd.
Example 2: an even integrand
∫−22(x2+∣x∣)dx=2∫02(x2+x)dx=2(38+2)=328
Example 3: mixed
Evaluate ∫−11(x5+3x2+sinx)dx.
The odd parts x5 and sinx vanish, leaving 2∫013x2dx=2.
Example 4: a periodic function
Evaluate ∫010π∣sinx∣dx.
The period is π and ∫0πsinxdx=2, so the answer is 10×2=20.
Example 5: fractional part
Evaluate ∫05{x}dx.
∫01xdx=21, so the answer is 5×21=25.
Example 6: Leibniz rule
Find dxd∫xx2tdt for x>0.
x21⋅2x−x1⋅1=x2−x1=x1
Summary table
| Idea | Key result |
|---|
| Odd over [−a, a] | 0 |
| Even over [−a, a] | Twice the integral over [0, a] |
| Periodic, n periods | n times one period |
| ∣sinx∣ | Period π, area 2 per period |
| Leibniz | f(h)h′−f(g)g′ |
Exam tips
- With symmetric limits, check parity before doing any integration.
- Split mixed integrands into odd and even parts.
- For long intervals of periodic functions, find one period's value and multiply.
See the area under curves for geometric applications, and the NIMCET Calculus chapter.
Common mistakes
- Using the odd-function result when limits are not symmetric.
- Treating ∣x∣ or xsinx as odd.
- Taking 2π as the period of ∣sinx∣.
- Forgetting the lower-limit term in the Leibniz rule.
Frequently Asked Questions
What is the integral of an odd function from −a to a?
It is 0.
What is the integral of an even function from −a to a?
It is 2∫₀ᵃ f(x) dx.
How do you integrate a periodic function over many periods?
Multiply the integral over one period by the number of periods.
What is the Leibniz rule?
d/dx ∫ from g(x) to h(x) of f(t) dt = f(h(x))h′(x) − f(g(x))g′(x).
Is the Leibniz rule in the NIMCET syllabus?
Reports on the revised syllabus list it as removed. Confirm with the official information brochure for your exam year.