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Dehydration of Ethanol to Ethene | Class 10 Science

Learn how ethanol is converted to ethene by heating with concentrated sulphuric acid at 443 K, why the acid is a dehydrating agent, and how this differs from oxidation, for Class 10.

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Updated 24 October 2026

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Quick answer: When ethanol is heated at 443 K with excess concentrated sulphuric acid, it loses a molecule of water and forms ethene: CH3CH2OH→hot conc. H2SO4, 443 KCH2=CH2+H2O\mathrm{CH_3CH_2OH \xrightarrow{\text{hot conc. } H_2SO_4,\ 443\ K} CH_2{=}CH_2 + H_2O}. This is called dehydration. Concentrated sulphuric acid acts as a dehydrating agent: it removes water from the ethanol.

Ethanol is a saturated compound: all its carbon–carbon bonds are single bonds. When it is heated with concentrated sulphuric acid, a molecule of water is removed from each ethanol molecule, and an unsaturated compound, ethene, is formed. Ethene has a carbon–carbon double bond.

In CBSE Class 10 Science, Chapter 4 (Carbon and its Compounds), the dehydration of ethanol and the role of concentrated sulphuric acid are frequently asked board exam questions.


What You Will Learn

  • What a dehydration reaction is
  • The equation for converting ethanol to ethene
  • The role of concentrated sulphuric acid
  • Why the reaction conditions (443 K, excess acid) matter
  • How to show that the gas formed is unsaturated
  • How dehydration differs from the oxidation of ethanol

1. What Is Dehydration?

Definition: A dehydration reaction is one in which a molecule of water is removed from a compound.

In the dehydration of ethanol, an −OH\mathrm{-OH} group is removed from one carbon atom and an H\mathrm{H} atom from the neighbouring carbon atom. Together they form H2O\mathrm{H_2O}, and a double bond forms between the two carbon atoms.


2. Ethanol to Ethene

Equation

CH3−CH2−OH→hot conc. H2SO4, 443 KCH2=CH2+H2O\mathrm{CH_3{-}CH_2{-}OH \xrightarrow{\text{hot conc. } H_2SO_4,\ 443\ K} CH_2{=}CH_2 + H_2O}

Reactant / productFormulaType
EthanolC2H5OH\mathrm{C_2H_5OH}Saturated alcohol
EtheneC2H4\mathrm{C_2H_4}Unsaturated hydrocarbon (alkene)
WaterH2O\mathrm{H_2O}Removed by the acid

Conditions

  • Temperature: 443 K443\text{ K} (170∘C170^\circ\text{C})
  • Reagent: excess concentrated sulphuric acid

3. Role of Concentrated Sulphuric Acid

Common board question: What is the role of concentrated sulphuric acid when ethanol is heated with it at 443 K?

Answer: Concentrated sulphuric acid acts as a dehydrating agent. It removes a molecule of water from ethanol, converting it into ethene.


4. Why the Conditions Matter (Extra)

Extra fact (beyond the Class 10 textbook): The product depends on the conditions. At about 443 K443\text{ K} with excess acid, ethene is the main product. At a lower temperature, about 413 K413\text{ K}, with excess ethanol, a different compound called diethyl ether (C2H5−O−C2H5\mathrm{C_2H_5{-}O{-}C_2H_5}) is formed instead.

So in your answer, always write 443 K and concentrated H2SO4\mathrm{H_2SO_4} with the reaction arrow.


5. Showing That Ethene Is Unsaturated (Extra)

Ethene has a carbon–carbon double bond, so it takes part in addition reactions. A common laboratory test is to bubble the gas through bromine water, which is reddish-brown. Ethene adds bromine across its double bond, and the colour disappears:

CH2=CH2+Br2⟶CH2Br−CH2Br\mathrm{CH_2{=}CH_2 + Br_2 \longrightarrow CH_2Br{-}CH_2Br}

Saturated compounds such as ethanol do not decolourise bromine water in this way.


6. Dehydration vs Oxidation of Ethanol

ReactionReagentProduct
DehydrationHot concentrated H2SO4\mathrm{H_2SO_4}, 443 KEthene, CH2=CH2\mathrm{CH_2{=}CH_2}
OxidationAlkaline potassium permanganate or acidified potassium dichromateEthanoic acid, CH3COOH\mathrm{CH_3COOH}

7. Summary Table

FeatureDetails
ReactantEthanol, CH3CH2OH\mathrm{CH_3CH_2OH}
ReagentExcess concentrated sulphuric acid
Temperature443 K
ProductEthene, CH2=CH2\mathrm{CH_2{=}CH_2}, and water
Role of the acidDehydrating agent

8. Exam Tips and Common Mistakes

Exam Tip: Always write the conditions with the arrow: hot conc. H2SO4\mathrm{H_2SO_4}, 443 K.

Exam Tip: Use the term dehydrating agent when describing the role of concentrated sulphuric acid.

Common Mistake: Confusing dehydration with oxidation. Dehydration gives ethene; oxidation gives ethanoic acid.

Common Mistake: Writing the product as ethane (C2H6\mathrm{C_2H_6}). The product is ethene (C2H4\mathrm{C_2H_4}), which has a double bond.


Frequently Asked Questions

What happens when ethanol is heated with concentrated sulphuric acid at 443 K?

Ethanol loses a molecule of water and forms ethene: CH₃CH₂OH → CH₂=CH₂ + H₂O.

What is the role of concentrated sulphuric acid in this reaction?

It acts as a dehydrating agent, removing water from ethanol.

What is a dehydration reaction?

A reaction in which a molecule of water is removed from a compound.

What is the product of oxidation of ethanol?

Ethanoic acid, using alkaline potassium permanganate or acidified potassium dichromate.

Is ethene saturated or unsaturated?

Ethene is unsaturated, because it has a carbon–carbon double bond.

Concept Check

HARD

An illuminated object placed 30 cm30\text{ cm} in front of a convex lens produces a sharp real image on a screen situated 60 cm60\text{ cm} on the opposite side of the lens. What is the focal length of the lens, and where will the image form if the object is moved to 40 cm40\text{ cm} from the lens?

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