NIMCET, GATE, CUET & CBSE test series are live — start practicing free
syllabuzAI

Force on a Current-Carrying Conductor & Fleming's Left-Hand Rule: Class 10

Master the mechanical force on a current-carrying conductor in a magnetic field for CBSE Class 10 Science. Explore the kicking wire experiment, maximum force conditions (F = BIl sin θ), and Fleming's Left-Hand Rule for electric motors.

7 min read

S2

scholar 247

Updated 14 September 2026

On this page

When Oersted discovered that an electric current deflects a magnetic compass needle, French physicist André-Marie Ampère reasoned through Newton's Third Law of Motion: If an electric current exerts a mechanical force on a magnet, then the magnet must exert an equal and opposite mechanical force on the current-carrying conductor!

This reciprocal principle is not merely a theoretical curiosity—it is the foundational physics engine that powers our modern mechanical civilization. Every electric ceiling fan spinning overhead, every electric car accelerating silently on the highway, and every washing machine motor operates on the mechanical force exerted on a current-carrying conductor in a magnetic field.

In CBSE Class 10 Science, Chapter 12 (Magnetic Effects of Electric Current), mastering the kicking wire experiment and applying Fleming's Left-Hand Rule are high-yield requirements for scoring top marks.


What You Will Learn

  • Ampère's hypothesis and the reciprocal force principle
  • The classic Kicking Wire Experiment (NCERT Activity 12.7)
  • Conditions under which the magnetic force is maximum and zero
  • Statement and fingers mapping of Fleming's Left-Hand Rule
  • Memory mnemonic: Father, Mother, Child (F−M−CF - M - C)
  • The basic principle of the Electric Motor
  • Solved CBSE board examination directional problems and common traps

1. The Reciprocal Force: Ampère's Hypothesis

If a magnet exerts a force on an iron nail, the nail exerts an equal and opposite force on the magnet. Ampère extended this logic to electromagnetism:

  • A current-carrying wire exerts a force that deflects a magnetic needle.
  • Therefore, when a current-carrying wire is placed inside an external magnetic field, the magnetic field must exert a physical mechanical force on the wire, pushing or displacing it!

2. The Kicking Wire Experiment (NCERT Activity 12.7)

To demonstrate this mechanical force in the laboratory:

                            Horseshoe Magnet
                                   | N |
                                   |   |
    Support ─── (Flexible Wire) ───[ Al Rod AB ]─── (Flexible Wire) ─── Battery & Key
                                   |   |
                                   | S |
                         Rod AB kicks OUTWARD / INWARD!

Experimental Setup:

  1. A small aluminum rod ABAB is suspended horizontally by flexible connecting wires between the two poles of a powerful horseshoe magnet, such that the rod lies between the North and South poles.
  2. The magnetic field is directed vertically upwards (from NN to SS).
  3. An electric current is passed through the rod from end BB to end AA.

Experimental Observations:

  • The moment current flows, the rod is physically displaced (kicked) towards the left!
  • If the direction of current is reversed (from AA to BB), the rod is displaced in the opposite direction (towards the right).
  • If the magnetic poles are reversed (field directed downwards), the direction of displacement reverses again.

Conclusion: <u>A mechanical force is exerted on a current-carrying conductor placed in an external magnetic field. The direction of this force depends upon BOTH the direction of the current and the direction of the magnetic field!</u>


3. When is the Mechanical Force Maximum and Zero?

The magnitude of the mechanical force (FF) acting on a conductor of length ll carrying current II inside a magnetic field BB is given by: F=B×I×l×sin⁡θ\mathbf{F = B \times I \times l \times \sin \theta} where θ\theta is the angle between the direction of the current and the direction of the magnetic field.

    Case 1: Perpendicular (θ = 90°)                  Case 2: Parallel (θ = 0° or 180°)
               Magnetic Field (B)                               Current (I)
                       ^                                ──────────────────────────>
                       |                                ──────────────────────────>
                       |                                    Magnetic Field (B)
        Current (I) ───+───> (θ = 90°)
             FORCE IS MAXIMUM! (F = BIl)                     FORCE IS ZERO! (F = 0)
  1. Maximum Force (θ=90∘\theta = 90^\circ): The displacement of the rod is largest when the direction of current is strictly perpendicular (90∘90^\circ) to the direction of the magnetic field: Fmax=BIl(when sin⁡90∘=1)\mathbf{F_{\text{max}} = B I l \quad (\text{when } \sin 90^\circ = 1)}
  2. Zero Force (θ=0∘ or 180∘\theta = 0^\circ \text{ or } 180^\circ): <u>If the conductor is placed parallel or anti-parallel to the magnetic field lines, NO mechanical force acts on the conductor (F=0F = 0)!</u>

4. Fleming's Left-Hand Rule: Predicting Force Direction

To predict the direction of the mechanical force (motion) acting on a conductor, we use Fleming's Left-Hand Rule:

                                  THUMB = Force / Motion (F)
                                      ^
                                      |
                           FOREFINGER = Magnetic Field (B)
                                      ^
                                     /
                                    /
                        +----------+
                        |  LEFT    |
                        |  HAND    |
                        +----------+
                                                                         v
                        MIDDLE FINGER = Current (I)

Formal Statement

Stretch the thumb, forefinger, and middle finger of your left hand mutually perpendicular to one another. If the forefinger points in the direction of the magnetic field and the middle finger points in the direction of electric current, then the thumb will point in the direction of motion or the mechanical force acting on the conductor.

The "Father - Mother - Child" Memory Mnemonic:

To avoid confusing the three fingers during high-pressure board exams:

  • Thumb   ⟹  \implies Force / Motion (Father)
  • Forefinger   ⟹  \implies Magnetic Field (Mother)
  • Center (Middle) Finger   ⟹  \implies Current (Child) F−M−C⟺Force−Magnetic Field−Current\mathbf{F - M - C \quad \Longleftrightarrow \quad \text{Force} - \text{Magnetic Field} - \text{Current}}

5. Working Principle of an Electric Motor

An electric motor is a rotating machine that converts electrical energy into mechanical energy.

  • Underlying Principle: An electric motor works on the principle of Fleming's Left-Hand Rule: When a rectangular coil carrying electric current is placed in a magnetic field, equal and opposite forces act on its two parallel arms, creating a torque that rotates the coil continuously.
  • The Role of the Split-Ring Commutator: <u>The split-ring commutator reverses the direction of current through the rotating coil every half rotation, ensuring that the coil continues to rotate in the SAME direction!</u>

6. Solved CBSE Board Examination Directional Problems

Solved Example 1: Alpha Particle Deflection (CBSE Board Classic)

Problem: A positively charged particle (alpha particle) projected towards the west is deflected towards the north by a magnetic field. What is the direction of the magnetic field?

Solution:

  1. Identify the Given Vectors:
    • The alpha particle has a positive charge. Therefore, the direction of conventional current (II) is the same as the direction of motion of the alpha particle   ⟹  \implies Current (II) is towards the West.
    • The particle is deflected towards the north   ⟹  \implies Force (FF) is towards the North.
    • We must find the direction of the Magnetic Field (BB).
  2. Apply Fleming's Left-Hand Rule:
    • Point your left thumb (Force) towards the North.
    • Point your left middle finger (Current) towards the West.
    • Your outstretched forefinger (Magnetic Field) will naturally point vertically UPWARDS (out of the page)!
  3. Therefore, <u>the direction of the magnetic field is vertically UPWARDS</u>.

Solved Example 2: Electron Beam in a Magnetic Field

Problem: An electron enters a magnetic field at right angles to it, as shown. What is the direction of force acting on the electron? (Diagram shows Magnetic Field pointing into the page, and Electron moving from top to bottom).

Solution:

  1. Analyze Electron Motion:
    • An electron carries a negative charge.
    • By definition, the direction of conventional current (II) is opposite to the direction of electron motion.
    • Since electrons move downwards, the Current (II) is directed UPWARDS.
  2. Analyze Magnetic Field:
    • The magnetic field (BB) is directed into the page (perpendicularly inward).
  3. Apply Fleming's Left-Hand Rule:
    • Forefinger (Field) points into the page.
    • Middle finger (Current) points Upwards.
    • Your left thumb (Force) will point towards the LEFT!
  4. Therefore, <u>the direction of force acting on the electron is towards the LEFT</u>.

7. Summary and Examination Tips

FingerRepresentsMemory Aid
ThumbMotion / Force (FF)Father
ForefingerMagnetic Field (BB)Mother
Middle FingerCurrent (II)Child

Exam Tip: In questions involving electrons or beta particles, remember that Current is OPPOSITE to electron movement! Forgetting to reverse the direction for negative charges is the most common student error in board exams.

Common Mistake: Using the right hand instead of the left hand for motors or force problems. Fleming's LEFT-hand rule is for motors and mechanical force; Fleming's RIGHT-hand rule is for generators and induced currents!

Concept Check

MEDIUM

Given that HCF(336,54)=6\text{HCF}(336, 54) = 6, find LCM(336,54)\text{LCM}(336, 54).

Suggested for you