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Introduction to Polynomials for CBSE Class 10 Mathematics

Master the fundamentals of polynomials for CBSE Class 10 Mathematics. Understand standard algebraic form, identifying valid polynomials, terms, coefficients, and finding the value of a polynomial with solved board examples.

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Updated 14 September 2026

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Algebra provides the language through which mathematical relationships and patterns are expressed. At the heart of school algebra lies the concept of a polynomial. Derived from the Greek word poly (meaning "many") and the Latin nomen / nomial (meaning "term" or "name"), a polynomial is an algebraic expression composed of variables, constants, and arithmetic operations.

In CBSE Class 10 Mathematics, understanding polynomials is essential because they form the direct foundation for quadratic equations, coordinate graphing of curves, and polynomial functions in higher mathematics.


What You Will Learn

  • Formal definition and standard mathematical form of a polynomial
  • The non-negative integer exponent condition
  • How to distinguish polynomials from general algebraic expressions
  • Anatomy of a polynomial: terms, coefficients, and constant terms
  • Calculating the value of a polynomial P(x)P(x) at x=kx = k
  • Step-by-step solved examples and board exam questions
  • Common pitfalls and student mistakes to avoid

1. What is a Polynomial?

A polynomial in one variable xx is an algebraic expression in which the powers of the variable are strictly non-negative integers (whole numbers).

Standard Form of a Polynomial

A polynomial P(x)P(x) of degree nn in variable xx is written in standard form as:

P(x)=anxn+an−1xn−1+an−2xn−2+⋯+a1x+a0P(x) = a_n x^n + a_{n-1} x^{n-1} + a_{n-2} x^{n-2} + \dots + a_1 x + a_0

where:

  • xx is the variable.
  • an,an−1,…,a1,a0a_n, a_{n-1}, \dots, a_1, a_0 are real numbers known as the coefficients of the polynomial.
  • an≠0a_n \ne 0 is the leading coefficient.
  • a0a_0 is the constant term.
  • nn is a non-negative integer (n∈{0,1,2,3,… }n \in \{0, 1, 2, 3, \dots\}), representing the degree of the polynomial.

Important: <u>The exponent of the variable xx in every term of a polynomial must be a non-negative integer. If any term contains a negative exponent, a fractional exponent, or a variable in the denominator or under a radical, the expression is NOT a polynomial.</u>


2. Identifying Polynomials vs. Non-Polynomials

To determine whether an algebraic expression is a polynomial, inspect the exponents of the variable in each term after algebraic simplification.

Valid Polynomial Expressions

  • P(x)=3x2−5x+7P(x) = 3x^2 - 5x + 7 (Exponents are 2, 1, 0   ⟹  \implies Valid polynomial)
  • Q(y)=2y3−34y+9Q(y) = \sqrt{2} y^3 - \frac{3}{4} y + 9 (The coefficients 2\sqrt{2} and −34-\frac{3}{4} are real numbers, and exponents of yy are 3, 1   ⟹  \implies Valid polynomial)
  • R(t)=t4−8R(t) = t^4 - 8 (Exponents are 4, 0   ⟹  \implies Valid polynomial)

Expressions That Are NOT Polynomials

  • f(x)=2x2+3x−5f(x) = 2x^2 + \frac{3}{x} - 5: Here 3x=3x−1\frac{3}{x} = 3x^{-1}. Since the exponent is −1-1 (negative), this is not a polynomial.
  • g(x)=x+4xg(x) = \sqrt{x} + 4x: Here x=x1/2\sqrt{x} = x^{1/2}. Since the exponent is 12\frac{1}{2} (a fraction, not an integer), this is not a polynomial.
  • h(x)=1x2+2x+1h(x) = \frac{1}{x^2 + 2x + 1}: The variable expression appears in the denominator. This is a rational algebraic fraction, not a polynomial.

Remember: Real numbers (even square roots like 3\sqrt{3} or π\pi) can serve as coefficients. The restriction applies strictly to the exponent of the variable, not to the numerical coefficients!


3. Anatomy of a Polynomial

Let us dissect the polynomial P(x)=5x3−4x2+7x−9P(x) = 5x^3 - 4x^2 + 7x - 9:

ComponentDescription in P(x)=5x3−4x2+7x−9P(x) = 5x^3 - 4x^2 + 7x - 9
TermsThe individual parts separated by ++ or −-: 5x3,−4x2,7x,5x^3, -4x^2, 7x, and −9-9
Leading TermThe term with the highest power of xx: 5x35x^3
Leading CoefficientThe coefficient of the leading term: 55
Coefficient of x2x^2The numerical multiplier of x2x^2: −4-4
Coefficient of xxThe numerical multiplier of xx: 77
Constant TermThe term independent of variable xx: −9-9

4. Value of a Polynomial at a Given Point

If P(x)P(x) is a polynomial in variable xx, and kk is any real number, then the value obtained by substituting x=kx = k in P(x)P(x) is called the value of P(x)P(x) at x=kx = k, denoted by P(k)P(k).

Solved Example 1: Evaluating a Polynomial

Problem: If P(x)=2x3−3x2+4x−5P(x) = 2x^3 - 3x^2 + 4x - 5, find P(2)P(2) and P(−1)P(-1).

Solution:

  1. Finding P(2)P(2): Substitute x=2x = 2 into the expression: P(2)=2(2)3−3(2)2+4(2)−5P(2) = 2(2)^3 - 3(2)^2 + 4(2) - 5 P(2)=2(8)−3(4)+8−5=16−12+8−5=7P(2) = 2(8) - 3(4) + 8 - 5 = 16 - 12 + 8 - 5 = 7
  2. Finding P(−1)P(-1): Substitute x=−1x = -1: P(−1)=2(−1)3−3(−1)2+4(−1)−5P(-1) = 2(-1)^3 - 3(-1)^2 + 4(-1) - 5 P(−1)=2(−1)−3(1)−4−5=−2−3−4−5=−14P(-1) = 2(-1) - 3(1) - 4 - 5 = -2 - 3 - 4 - 5 = -14

Solved Example 2: CBSE Board Question

Problem: State with reason whether the expression E(x)=x2+2x+5E(x) = x^2 + \frac{2}{\sqrt{x}} + 5 is a polynomial.

Solution:

  1. Rewrite the expression in exponential form: E(x)=x2+2x−1/2+5E(x) = x^2 + 2x^{-1/2} + 5
  2. Observe the second term: the exponent of xx is −12-\frac{1}{2}.
  3. For an expression to be a polynomial, all exponents of the variable must be non-negative integers.
  4. Since −12-\frac{1}{2} is a negative fraction, <u>E(x)E(x) is not a polynomial</u>.

5. Summary and Examination Tips

Key CharacteristicPolynomial Rule
Allowed OperationsAddition, subtraction, multiplication of variables and constants
Variable ExponentsMust be elements of {0,1,2,3,… }\{0, 1, 2, 3, \dots\} (whole numbers)
CoefficientsAny real numbers (integers, fractions, irrational numbers)
EvaluationP(k)P(k) is obtained by direct substitution of x=kx = k

Exam Tip: When writing a polynomial in board exams, always arrange the terms in descending order of their exponents (standard form). For example, write 4x3−2x2+x−84x^3 - 2x^2 + x - 8 rather than x−2x2−8+4x3x - 2x^2 - 8 + 4x^3.

Common Mistake: Confusing the coefficient with the exponent. In 5x2\sqrt{5}x^2, the coefficient is irrational, but the exponent is 22 (a whole number), so it IS a polynomial. In 5x5\sqrt{x}, the exponent is 12\frac{1}{2}, so it is NOT a polynomial.

Concept Check

EXPERT

If the quadratic equations x2+ax+b=0x^2 + ax + b = 0 and x2+bx+a=0x^2 + bx + a = 0 (where a≠ba \neq b) share a common root, what is the value of this common root and the sum of coefficients (a+b)(a + b)?

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