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Statistics: Grouped Data, Missing Frequencies & Ogives Class 10

Master Chapter 13 of CBSE Class 10 Mathematics: Statistics. Comprehensive guide covering Mean methods, Mode formula, the classic 5-mark Median missing frequencies (x and y) problem, Pearson's empirical relation, and Ogives.

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Updated 14 September 2026

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In modern data science, business forecasting, and medical research, decisions are governed by statistical distributions. In CBSE Class 10 Mathematics, Chapter 13 (Statistics) carries between 77 and 99 marks. It tests computational precision across the three measures of central tendency—Mean, Mode, and Median—along with the celebrated two missing frequencies (xx and yy) problem and the graphical determination of the median via Ogives.

In this master guide, we review the exact formulas, algebraic shortcuts, and presentation templates needed to secure full marks.


What You Will Learn

  • Comparison of the three methods to calculate the Mean: Direct, Assumed Mean, and Step-Deviation
  • The Mode Formula: Identifying the modal class and the 0−1−20 - 1 - 2 frequency subscripts
  • The Median Formula and constructing cumulative frequency (cfcf) tables
  • Complete 5-mark solution to the Missing Frequencies (xx and yy) Problem
  • Karl Pearson's Empirical Relationship: 3 Median=Mode+2 Mean3\,\text{Median} = \text{Mode} + 2\,\text{Mean}
  • Ogives (Cumulative Frequency Curves): Less than and More than ogives
  • Graphical determination of the median (N/2N/2 projection and double-ogive intersection)

1. Master Formula Compendium for Grouped Data

    1. MEAN (Step-Deviation):    x̄ = a + [ (Σ fi ui) / (Σ fi) ] × h      where ui = (xi - a) / h
    2. MODE:                     Mode = l + [ (f1 - f0) / (2f1 - f0 - f2) ] × h
    3. MEDIAN:                   Median = l + [ (N/2 - cf) / f ] × h     (cf is PRECEDING class!)
    4. EMPIRICAL RELATION:       3 Median = Mode + 2 Mean

2. Solving the 5-Mark Missing Frequencies Problem (xx and yy)

This problem appears in Section D of CBSE board exams almost every year:

Problem Statement:

The median of the following frequency distribution of 6060 observations is 28.528.5. Find the values of xx and yy:

Class Interval0−100 - 1010−2010 - 2020−3020 - 3030−4030 - 4040−5040 - 5050−6050 - 60Total
Frequency55xx20201515yy556060

Step-by-Step Solution:

Step 1: Construct the Cumulative Frequency (cfcf) Table:

Class IntervalFrequency (fif_i)Cumulative Frequency (cfcf)
0−100 - 105555
10−2010 - 20xx5+x5 + x
20−3020 - 30 (Median Class)2020 (ff)25+x25 + x
30−4030 - 40151540+x40 + x
40−5040 - 50yy40+x+y40 + x + y
50−6050 - 605545+x+y45 + x + y
TotalN=60N = 60—

Step 2: Establish Equation 1 from Total Frequency (N=60N = 60)

The sum of all frequencies must equal 6060: 45+x+y=6045 + x + y = 60 x+y=60−45  ⟹  x+y=15— (Equation 1)x + y = 60 - 45 \implies \mathbf{x + y = 15} \quad \text{--- (Equation 1)}

Step 3: Identify the Median Class from the Given Median (28.528.5)

  • The given median is 28.528.5.
  • 28.528.5 lies in the class interval 20−3020 - 30.
  • Therefore, the Median Class is 20−3020 - 30!

Step 4: Extract All Parameters:

  • Lower limit of median class: l=20l = \mathbf{20}
  • Class size: h=30−20=10h = 30 - 20 = \mathbf{10}
  • Frequency of median class: f=20f = \mathbf{20}
  • Half of total frequency: N2=602=30\frac{N}{2} = \frac{60}{2} = \mathbf{30}
  • Cumulative frequency of preceding class: cf=5+xcf = \mathbf{5 + x}

Step 5: Substitute into the Median Formula:

Median=l+(N2−cff)×h\text{Median} = l + \left( \frac{\frac{N}{2} - cf}{f} \right) \times h 28.5=20+(30−(5+x)20)×1028.5 = 20 + \left( \frac{30 - (5 + x)}{20} \right) \times 10 28.5−20=30−5−x228.5 - 20 = \frac{30 - 5 - x}{2} 8.5=25−x28.5 = \frac{25 - x}{2} 8.5×2=25−x  ⟹  17=25−x8.5 \times 2 = 25 - x \implies 17 = 25 - x x=25−17=8\mathbf{x = 25 - 17 = 8}

Step 6: Solve for yy using Equation 1:

x+y=15  ⟹  8+y=15  ⟹  y=15−8=7x + y = 15 \implies 8 + y = 15 \implies \mathbf{y = 15 - 8 = 7}

Step 7: State the Final Answer:

<u>The missing frequencies are x=8\mathbf{x = 8} and y=7\mathbf{y = 7}.</u>


3. Graphical Determination of the Median (Ogives)

An Ogive is a smooth cumulative frequency curve:

  1. Less Than Ogive: Plot Upper Class Limits on the xx-axis against Less than cumulative frequencies on the yy-axis (an ascending S-curve).
  2. More Than Ogive: Plot Lower Class Limits on the xx-axis against More than cumulative frequencies on the yy-axis (a descending S-curve).
    Cumulative                       Intersection of Both Ogives
    Frequency (cf)
         ^          \                             /  (Less than ogive)
       N |           \                           /
         |            \                         /
     N/2 + - - - - - - \ - - - - - - - - - - - /
         |              \         P           /
         |               \        *          /
         |                \      / \        /
         | (More than)     \    /   \      /
         |                  \  /     \    /
         +-------------------+--------+--+-------------------------->
         O                            M (MEDIAN on x-axis)

The Two Graphical Methods:

  • Method 1 (Single Ogive): On the yy-axis of a Less Than Ogive, locate N2\frac{N}{2}. Draw a horizontal line to intersect the curve at point PP. Drop a perpendicular from PP to the xx-axis. The xx-coordinate gives the Median!
  • Method 2 (Double Ogive): The xx-coordinate of the point of intersection of the Less Than and More Than ogives gives the exact Median!

4. Summary and Examination Tips

MetricEssential PrerequisiteCommon Mistake
MeanCalculate class marks xi=upper+lower2x_i = \frac{\text{upper}+\text{lower}}{2}Forgetting to multiply by hh in step-deviation
ModeIdentify modal class (highest f1f_1)Writing f1−f0−f2f_1 - f_0 - f_2 instead of 2f12f_1
MedianConstruct cfcf columnSubstituting median class cfcf instead of preceding
OgivesLess than uses Upper LimitsPlotting class marks instead of class limits

Exam Tip: In the missing frequency problem, never search for N/2=30N/2 = 30 in the cfcf column to find the median class! The median class is determined directly by where the given number (28.528.5) falls (in 20−3020-30)!

Common Mistake: Forgetting parentheses when subtracting cfcf in the median formula: 30−(5+x)=30−5−x=25−x30 - (5 + x) = 30 - 5 - x = 25 - x. Writing 30−5+x=25+x30 - 5 + x = 25 + x ruins the entire solution!

Concept Check

MEDIUM

Evaluate tan⁡−1(1)+cos⁡−1(−12)+sin⁡−1(−12)\tan^{-1}(1) + \cos^{-1}\left(-\frac{1}{2}\right) + \sin^{-1}\left(-\frac{1}{2}\right).

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