Quick answer: For the circle S : x 2 + y 2 + 2 g x + 2 f y + c = 0 S: x^2 + y^2 + 2gx + 2fy + c = 0 S : x 2 + y 2 + 2 g x + 2 f y + c = 0 , the tangent at ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) is T = 0 T = 0 T = 0 , where T = x x 1 + y y 1 + g ( x + x 1 ) + f ( y + y 1 ) + c T = xx_1 + yy_1 + g(x + x_1) + f(y + y_1) + c T = x x 1 + y y 1 + g ( x + x 1 ) + f ( y + y 1 ) + c . The line y = m x + c y = mx + c y = m x + c touches x 2 + y 2 = a 2 x^2 + y^2 = a^2 x 2 + y 2 = a 2 when c 2 = a 2 ( 1 + m 2 ) c^2 = a^2(1 + m^2) c 2 = a 2 ( 1 + m 2 ) . The length of the tangent from an external point is S 1 \sqrt{S_1} S 1 , and the chord of contact from that point is also T = 0 T = 0 T = 0 .
This continues from the equation of a circle .
Notation
Symbol Meaning S S S x 2 + y 2 + 2 g x + 2 f y + c x^2 + y^2 + 2gx + 2fy + c x 2 + y 2 + 2 g x + 2 f y + c S 1 S_1 S 1 S evaluated at ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) T T T x x 1 + y y 1 + g ( x + x 1 ) + f ( y + y 1 ) + c xx_1 + yy_1 + g(x + x_1) + f(y + y_1) + c x x 1 + y y 1 + g ( x + x 1 ) + f ( y + y 1 ) + c
For x 2 + y 2 = a 2 x^2 + y^2 = a^2 x 2 + y 2 = a 2 , T T T is simply x x 1 + y y 1 − a 2 xx_1 + yy_1 - a^2 x x 1 + y y 1 − a 2 .
Tangents
Situation Tangent At ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) on x 2 + y 2 = a 2 x^2 + y^2 = a^2 x 2 + y 2 = a 2 x x 1 + y y 1 = a 2 xx_1 + yy_1 = a^2 x x 1 + y y 1 = a 2 At ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) on the general circle T = 0 T = 0 T = 0 Slope m to x 2 + y 2 = a 2 x^2 + y^2 = a^2 x 2 + y 2 = a 2 y = m x ± a 1 + m 2 y = mx \pm a\sqrt{1 + m^2} y = m x ± a 1 + m 2 Parametric point θ on x 2 + y 2 = a 2 x^2 + y^2 = a^2 x 2 + y 2 = a 2 x cos θ + y sin θ = a x\cos\theta + y\sin\theta = a x cos θ + y sin θ = a
Condition of tangency: y = m x + c y = mx + c y = m x + c touches x 2 + y 2 = a 2 x^2 + y^2 = a^2 x 2 + y 2 = a 2 if
c 2 = a 2 ( 1 + m 2 ) c^2 = a^2(1 + m^2) c 2 = a 2 ( 1 + m 2 )
Normal
The normal at any point passes through the centre . So the normal at ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) is the line joining ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) to ( − g , − f ) (-g, -f) ( − g , − f ) .
Length of tangent and power of a point
From an external point P ( x 1 , y 1 ) P(x_1, y_1) P ( x 1 , y 1 ) :
Length of tangent = S 1 \text{Length of tangent} = \sqrt{S_1} Length of tangent = S 1
S 1 S_1 S 1 is called the power of the point. It is positive outside, zero on the circle, and negative inside.
Chord Equation Chord of contact from ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) T = 0 T = 0 T = 0 Chord with midpoint ( x 1 , y 1 ) (x_1, y_1) ( x 1 , y 1 ) T = S 1 T = S_1 T = S 1
Two circles
Let the centres be C 1 , C 2 C_1, C_2 C 1 , C 2 , the radii r 1 , r 2 r_1, r_2 r 1 , r 2 , and d = C 1 C 2 d = C_1C_2 d = C 1 C 2 .
Condition Position Common tangents d > r 1 + r 2 d > r_1 + r_2 d > r 1 + r 2 Separate 4 d = r 1 + r 2 d = r_1 + r_2 d = r 1 + r 2 Touch externally 3 ∣ r 1 − r 2 ∣ < d < r 1 + r 2 \lvert r_1 - r_2\rvert < d < r_1 + r_2 ∣ r 1 − r 2 ∣ < d < r 1 + r 2 Intersect 2 d = ∣ r 1 − r 2 ∣ d = \lvert r_1 - r_2\rvert d = ∣ r 1 − r 2 ∣ Touch internally 1 d < ∣ r 1 − r 2 ∣ d < \lvert r_1 - r_2\rvert d < ∣ r 1 − r 2 ∣ One inside the other 0
Orthogonal circles (tangents at an intersection point are perpendicular):
2 g 1 g 2 + 2 f 1 f 2 = c 1 + c 2 2g_1g_2 + 2f_1f_2 = c_1 + c_2 2 g 1 g 2 + 2 f 1 f 2 = c 1 + c 2
Family of circles
Family Equation Through the intersection of circle S and line L S + λ L = 0 S + \lambda L = 0 S + λ L = 0 Through the intersection of two circles S 1 + λ S 2 = 0 S_1 + \lambda S_2 = 0 S 1 + λ S 2 = 0 (λ ≠ − 1 \lambda \ne -1 λ = − 1 )Common chord of two circles S 1 − S 2 = 0 S_1 - S_2 = 0 S 1 − S 2 = 0
Worked examples
Example 1: tangent at a point
Find the tangent to x 2 + y 2 = 25 x^2 + y^2 = 25 x 2 + y 2 = 25 at ( 3 , 4 ) (3, 4) ( 3 , 4 ) .
3 x + 4 y = 25 3x + 4y = 25 3 x + 4 y = 25 .
Example 2: tangency condition
For what c does y = 2 x + c y = 2x + c y = 2 x + c touch x 2 + y 2 = 5 x^2 + y^2 = 5 x 2 + y 2 = 5 ?
c 2 = 5 ( 1 + 4 ) = 25 c^2 = 5(1 + 4) = 25 c 2 = 5 ( 1 + 4 ) = 25 , so c = ± 5 c = \pm 5 c = ± 5 .
Example 3: length of tangent
Find the tangent length from ( 5 , 1 ) (5, 1) ( 5 , 1 ) to x 2 + y 2 − 2 x + 4 y − 4 = 0 x^2 + y^2 - 2x + 4y - 4 = 0 x 2 + y 2 − 2 x + 4 y − 4 = 0 .
S 1 = 25 + 1 − 10 + 4 − 4 = 16 S_1 = 25 + 1 - 10 + 4 - 4 = 16 S 1 = 25 + 1 − 10 + 4 − 4 = 16 , so the length is 4.
Example 4: orthogonal circles
Check whether x 2 + y 2 − 2 x − 4 y + 1 = 0 x^2 + y^2 - 2x - 4y + 1 = 0 x 2 + y 2 − 2 x − 4 y + 1 = 0 and x 2 + y 2 + 4 x − 2 y + 3 = 0 x^2 + y^2 + 4x - 2y + 3 = 0 x 2 + y 2 + 4 x − 2 y + 3 = 0 are orthogonal.
g 1 = − 1 g_1 = -1 g 1 = − 1 , f 1 = − 2 f_1 = -2 f 1 = − 2 , c 1 = 1 c_1 = 1 c 1 = 1 ; g 2 = 2 g_2 = 2 g 2 = 2 , f 2 = − 1 f_2 = -1 f 2 = − 1 , c 2 = 3 c_2 = 3 c 2 = 3 .
2 ( − 1 ) ( 2 ) + 2 ( − 2 ) ( − 1 ) = − 4 + 4 = 0 2(-1)(2) + 2(-2)(-1) = -4 + 4 = 0 2 ( − 1 ) ( 2 ) + 2 ( − 2 ) ( − 1 ) = − 4 + 4 = 0 , but c 1 + c 2 = 4 c_1 + c_2 = 4 c 1 + c 2 = 4 , so they are not orthogonal.
Changing the first circle to x 2 + y 2 − 2 x − 4 y − 3 = 0 x^2 + y^2 - 2x - 4y - 3 = 0 x 2 + y 2 − 2 x − 4 y − 3 = 0 gives c 1 + c 2 = 0 c_1 + c_2 = 0 c 1 + c 2 = 0 , and then they are orthogonal.
Summary table
Result Formula Tangent at a point T = 0 T = 0 T = 0 Tangency condition c 2 = a 2 ( 1 + m 2 ) c^2 = a^2(1 + m^2) c 2 = a 2 ( 1 + m 2 ) Tangent length S 1 \sqrt{S_1} S 1 Chord with midpoint T = S 1 T = S_1 T = S 1 Orthogonality 2 g 1 g 2 + 2 f 1 f 2 = c 1 + c 2 2g_1g_2 + 2f_1f_2 = c_1 + c_2 2 g 1 g 2 + 2 f 1 f 2 = c 1 + c 2
Exam tips
Make sure the coefficients of x 2 x^2 x 2 and y 2 y^2 y 2 are 1 before computing S 1 S_1 S 1 .
Count common tangents by comparing d with r 1 + r 2 r_1 + r_2 r 1 + r 2 and ∣ r 1 − r 2 ∣ \lvert r_1 - r_2\rvert ∣ r 1 − r 2 ∣ .
The common chord is found by subtracting the two circle equations.
Next, study the parabola: focus, directrix and standard forms , or see the NIMCET Coordinate Geometry and Vectors chapter .
Common mistakes
Using T = 0 T = 0 T = 0 for the chord with a given midpoint; it is T = S 1 T = S_1 T = S 1 .
Forgetting the ± sign in y = m x ± a 1 + m 2 y = mx \pm a\sqrt{1 + m^2} y = m x ± a 1 + m 2 .
Computing tangent length from a point inside the circle.
Using the orthogonality condition with unhalved coefficients.
Frequently Asked Questions
What is the equation of the tangent to x² + y² = a² at (x₁, y₁)?
xx₁ + yy₁ = a².
What is the condition for y = mx + c to be a tangent to x² + y² = a²?
c² = a²(1 + m²).
What is the length of the tangent from a point to a circle?
It is √S₁, where S₁ is the value of the circle's equation at that point.
What is the condition for two circles to be orthogonal?
2g₁g₂ + 2f₁f₂ = c₁ + c₂.
How many common tangents do two externally touching circles have?
Three.