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Harmonic Progression and AM-GM-HM Inequality | NIMCET

Learn harmonic progression, harmonic mean, the AM ≥ GM ≥ HM inequality and G² = AH, arithmetico-geometric series and how to use AM-GM for maximum and minimum problems in NIMCET.

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SHIVAM PRADHAN

Updated 25 October 2026

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Quick answer: A sequence is a harmonic progression (HP) if the reciprocals of its terms form an AP. The harmonic mean of a and b is H=2aba+bH = \frac{2ab}{a + b}. For positive a and b, A≥G≥HA \ge G \ge H, where A=a+b2A = \frac{a + b}{2} and G=abG = \sqrt{ab}, with equality only when a=ba = b, and G2=AHG^2 = AH. An arithmetico-geometric series multiplies an AP by a GP term by term.

This brings together arithmetic and geometric progressions.

Harmonic progression

If a1,a2,a3,…a_1, a_2, a_3, \ldots is an HP, then 1a1,1a2,1a3,…\frac{1}{a_1}, \frac{1}{a_2}, \frac{1}{a_3}, \ldots is an AP with common difference d, and

an=11a1+(n−1)da_n = \frac{1}{\frac{1}{a_1} + (n - 1)d}

There is no simple formula for the sum of an HP.

  • a, b, c are in HP if and only if b=2aca+cb = \frac{2ac}{a + c}.
  • Equivalently, a−bb−c=ac\frac{a - b}{b - c} = \frac{a}{c}.

The three means

MeanTwo numbers a, bn numbers
Arithmetic (A)a+b2\frac{a + b}{2}a1+…+ann\frac{a_1 + \ldots + a_n}{n}
Geometric (G)ab\sqrt{ab}(a1a2⋯an)1n(a_1a_2\cdots a_n)^{\frac{1}{n}}
Harmonic (H)2aba+b\frac{2ab}{a + b}n1a1+…+1an\frac{n}{\frac{1}{a_1} + \ldots + \frac{1}{a_n}}

Relations between the means

For positive numbers:

A≥G≥HA \ge G \ge H

with equality only when all numbers are equal. For two numbers, G2=AHG^2 = AH, so A, G, H are in GP.

Recovering the numbers: a and b are the roots of x2−2Ax+G2=0x^2 - 2Ax + G^2 = 0.

AM-GM for extreme values

For positive terms with a fixed product, the sum is smallest when the terms are equal; with a fixed sum, the product is largest when the terms are equal.

ExpressionExtreme value
x+1xx + \frac{1}{x}, x>0x > 0Minimum 2 at x=1x = 1
x+kxx + \frac{k}{x}, x,k>0x, k > 0Minimum 2k2\sqrt{k}
xyxy with x+y=sx + y = s, x,y>0x, y > 0Maximum s24\frac{s^2}{4}
(a+b)(1a+1b)(a + b)\left(\frac{1}{a} + \frac{1}{b}\right)Minimum 4

Arithmetico-geometric series

The general term is [a+(n−1)d]rn−1[a + (n - 1)d]r^{n - 1}. To sum it, write S, multiply by r, subtract, and sum the resulting GP.

For ∣r∣<1\lvert r\rvert < 1:

S∞=a1−r+dr(1−r)2S_\infty = \frac{a}{1 - r} + \frac{dr}{(1 - r)^2}

Worked examples

Example 1: nth term of an HP

Find the 10th term of the HP 12,15,18,…\frac{1}{2}, \frac{1}{5}, \frac{1}{8}, \ldots.

The reciprocals 2, 5, 8, … have d=3d = 3, so the 10th reciprocal is 2+27=292 + 27 = 29 and the term is 129\frac{1}{29}.

Example 2: the three means

For 4 and 16: A=10A = 10, G=8G = 8, H=12820=6.4H = \frac{128}{20} = 6.4.

Check: AH=64=G2AH = 64 = G^2 ✓.

Example 3: minimum by AM-GM

Find the minimum of 4x+9x4x + \frac{9}{x} for x>0x > 0.

4x+9x≥236=124x + \frac{9}{x} \ge 2\sqrt{36} = 12, with equality at 4x=9x4x = \frac{9}{x}, that is, x=32x = \frac{3}{2}.

Example 4: AGP sum

Find 1+2x+3x2+4x3+…1 + 2x + 3x^2 + 4x^3 + \ldots for ∣x∣<1\lvert x\rvert < 1.

Here a=1a = 1, d=1d = 1, r=xr = x:

S∞=11−x+x(1−x)2=1(1−x)2S_\infty = \frac{1}{1 - x} + \frac{x}{(1 - x)^2} = \frac{1}{(1 - x)^2}

Example 5: numbers from the means

The AM and GM of two numbers are 5 and 4. Find the numbers.

x2−10x+16=0x^2 - 10x + 16 = 0, so the numbers are 2 and 8.

Summary table

IdeaKey result
HPReciprocals form an AP
Harmonic mean2aba+b\frac{2ab}{a + b}
InequalityA≥G≥HA \ge G \ge H
Two numbersG2=AHG^2 = AH
Infinite AGPa1−r+dr(1−r)2\frac{a}{1 - r} + \frac{dr}{(1 - r)^2}

Exam tips

  • Turn every HP question into an AP question by taking reciprocals.
  • AM-GM needs positive terms; check before applying it.
  • Remember 1+2x+3x2+…=1(1−x)21 + 2x + 3x^2 + \ldots = \frac{1}{(1 - x)^2}; it appears in probability too.

Next, read matrices: types, multiplication and transpose, or browse the NIMCET Algebra chapter.

Common mistakes

  • Trying to use a sum formula for an HP.
  • Applying AM-GM to negative numbers.
  • Writing H=a+b2abH = \frac{a + b}{2ab}, which is the reciprocal of the correct value.
  • Forgetting that equality in AM ≥ GM needs equal terms, which may be impossible under the constraints.

Frequently Asked Questions

What is a harmonic progression?

A sequence whose reciprocals form an arithmetic progression.

What is the harmonic mean of two numbers?

H = 2ab/(a + b).

What is the relation between AM, GM and HM?

For positive numbers, AM ≥ GM ≥ HM. For two numbers, GM² = AM × HM.

What is the minimum value of x + 1/x for x > 0?

It is 2, reached at x = 1.

What is the sum of 1 + 2x + 3x² + … for |x| < 1?

It equals 1/(1 − x)².

Concept Check

MEDIUM

The angles of elevation of the top of a tower from two points 44 m and 99 m from its foot, on the same line, are complementary. What is the height of the tower?

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